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關於瀑布頂底溫度差算法(求物理高手)

Sep 28th 2013, 12:30

Ek(J) =M(kg) * g(m/s^2) * h(m)

= m*9.8*600

= 5880M (J) → 此處質量M的單位是kg

= 1400M (cal) → 1卡(cal) = 4.2 (J)

H(cal) = m(g)*s(cal/g-°C)*△T(°C) → 此處質量M的單位是g

= (1000M)*1*△T

= 1000M△T

而

H = Ek

1000M△T = 1400M

△T = 1.4°C

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